Thread: Re: [Dev-C++] info

 > why are they useless?  why equal to 0?  can i have more explanation?

Let's take this bit of code:
int loopb3()
{
  for (n = 9; n >= 1; n--)
   b3 = n;
  return b3;
}

The function loopb3 has a "for..." loop which moves the value of b3 from 
9 down to 0. It does nothing else. The function loopb3 will _always_ 
return 0, which is the final value of b3 after the loop is complete.
-- 
Bruce Fletcher
Stronsay, Orkney
<www.stronsay.co.uk/claremont>

Almost. The loop will end when n reaches 0. But the last assign will be
performed when n is 1. So the "loop" functions can be rewritten as:

n = 0;
h3 = 1;
return 1;

/pwm


On Fri, 4 Apr 2008, Bruce Fletcher (Stronsay) wrote:

>  > why are they useless?  why equal to 0?  can i have more explanation?
>
> Let's take this bit of code:
> int loopb3()
> {
>   for (n = 9; n >= 1; n--)
>    b3 = n;
>   return b3;
> }
>
> The function loopb3 has a "for..." loop which moves the value of b3 from
> 9 down to 0. It does nothing else. The function loopb3 will _always_
> return 0, which is the final value of b3 after the loop is complete.
> --
> Bruce Fletcher
> Stronsay, Orkney
> <www.stronsay.co.uk/claremont>
>
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